A few days ago
Math help. 1 question?
Write the algebraic expression using one variable for the following statement. Solve the equation and give all three answers.
Equation (1pt)
Solution (1pt)
The sum of the third and twice the first of three consecutive odd integers is 49. Find all three consecutive odd integers.
Top 2 Answers
A few days ago
Favorite Answer
Let x = the first integer. Therefore, the second odd integer is x+2, and the third odd integer is x+4.
2x (twice the first) + x+4 (the third) = 49
2x+x+4 = 49
3x+4 = 49
3x = 45
x = 15
The first integer is 15, the next odd integer is 17, and the third is 19.
2
A few days ago
let x be the first odd number
second= x+2
third= x+4
equation:
2x+x+4=49
solve:
add 2x and x
so
3x+4=49
to transpose 4 to the right side, cancel out 4 on the left by
minusing (not sure of the spelling) on both sides of the equation.
so
3x+4-4=49-4
3x=45
finally divide 3 on both sides to cancel out 3 on the left leaving us with x.
3x/3=45/3
so, x=15
15+2=17
15+4=19
check:
2(15)+19=49
49=49
it checks!!
therefore, the 3 consecutive odd integers are 15, 17 and 19.
0
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