A few days ago
Last Math question I need help with?
A business consultant has developed a management training course. She has determined that her yearly profit in hundreds of dollars from selling and conduction the course is given by p(x)=-2x^2+60x-25. How many courses should she sell to maximize her profit? What is the maximum profit?
What do I do here? Thanks for any help that I can get..
Top 2 Answers
A few days ago
Favorite Answer
Use the equation (-b)/(2a) to find the vertex of the parabola:
(-60)/[2(-2)]= -60/-4=15
She needs to sell 15 courses to maximize her profit.
Plug 15 back into your original equation:
p(15)= -2(15^2) + 60(15) -25
-2(225) + 900 – 25
-450 + 900 -25
425
Her maximum profit will be $425
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A few days ago
Algebraically, the maximum point onn a parabola with equation ax^2 + bx + c is found when x = -b/(2a)
So here x = -60/[2(-2)] = -60/-4 = 15
Then plug that in to get the maximum profit.
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