A few days ago
Anonymous

Find the maximum area of a rectangle with a perimeter of 144 inches. Explain?

Find the maximum area of a rectangle with a perimeter of 144 inches.

a)288 square inches

b)324 square inches

c)1024 square inches

d)1296 square inches

Top 8 Answers
A few days ago
Kobie D

Favorite Answer

if each side is 36

36×4=144

area 36×36=1296 not sure if thats the max but fits as ans

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A few days ago
Anonymous
love math! It involves thinking and that’s fun! (lol, sound like such a dork). Ok, let’s get cracking:

Perimeter is the sum of the outside edges of any thing, correct? Example, a square has an edge 2 units long- the perimeter will be 2 + 2 + 2 + 2 = 8. Easy? Ok.

Area is the product of the two edges: length and width. Since it’s a square, all edges will be 2 units long (for this example). So the area is 2 * 2 = 4.

Alright, now you’re simply taking the above two pieces of information and working backwards:

Perimeter = 144 inches. And there are given areas. Let’s start with the biggest number there- 1296 square inches. Can you find the square root of that? (This is one way of trying to solve this problem) Yes- it’s 36 inches. Well, that means that each side is 36 inches. Does 36 + 36 + 36 + 36 = 144? Yes! A square is also a form of rectangle, so there you go! There is your answer! Hope this helps 🙂

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A few days ago
Anonymous
so a parimeter is equal to the sum of all the sides.

side 1 + side 2 + side 3 + side 4 = p

area is represented by width times length

Width * Length = Area

So to answer this question you needto find out what the length and width of a rectangle with a 144 inch perimeter is.

so take 144 and divide by 4.

144/4 = 36 or

36 + 36 + 36 + 36 = 144

Now that makes a square and squares are rectangles. So, now take the width and length of the square and multiply them.

36 * 36 = 1296 inches squared.

your answer is D

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A few days ago
x
D) 1296 in^2

The rectangle with the largest area:perimeter ratio is always a square. A square has 4 equal sides, so divide 144 by 4 to get the length of each side. Each side is 36 inches. Area is length times width: 36 in x 36 in = 1296 sq in

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A few days ago
Anonymous
The answer is d.

It’s been awhile since I’ve delt with this type of math, but to find the answer, you just divide the perimeter by 4 (144/4=36) and this gives you the length of one side (and turns the rectangle into a square, which has the greatest area).

You then just take 36*36=1296.

Hope that helps.

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5 years ago
Anonymous
You can actually solve the equ. xy=100 (sideXside=area) & 2x+2y=40 (x+x+y+y or 2side+ 2side=perimeter) and solve top equ that x= 100/y. Plug that in to get 2(100/y)+2y=40. Start solving: (100/y)+y=20 y^2+20y+100. Factor to get (y+10)(y+10) so y=-10. Back to original 2 equ so x(-10)=100. And x=-10. BUT! Distances such as a real measurement can’t be negative so x AND y=10. Thus, the original rectangle is also a square. And that means another rectangle with same area but DIFF perimeter is NOT a square! Dont listen to the other answer!
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A few days ago
alecto02
Think of it this way:

The perimeter of a rectangle is the sum of it’s sides. Assuming that the shorter sides =x and the longer sides =y. You can write “2x + 2y = 144”. So solve that to “x+y=72”

Now find all the things that add up to 72 as x and y. Then because the area of a rectangle is x times y you can input the values you found and see what the largest number you get is that fits one of your multiple choice answers.

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A few days ago
A.V.R.
If p = perimeter and a one side, then the other side =(p/2)-a; area= ax((p/2)-a)=ap/2-a^2

wnhen area is maximum the differential of this function=0.

That is, p/2-2a=0; therefore a=p/4.

In this case p=144; a=36 and area=1296 sq. ins.

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