A few days ago
Kinematics problems…plz explain with steps.?
Q1) A body is displaced through 10 cm by a force of 50N in a direction making an angle of 60 degrees with the force. calculate the work done by the force. (ans is 250J)
Q2) A body is projected such that KE at the top is 3/4th KE at the point of projection. What is the angle of projection?
Q3) A person is standing on a truck moving with a constant velocity of 14.7m/s on a horizontal road, throws a ball in such a way that it returns to his hand after the truck has moved 58.8m. Find the speed and angle of projection:
a) as seen from the truck (ans is 19.6m/s upwards)
b) as seen from the road (ans is 24.5m/s at 56 degrees 3 min
with the horizontal)
Top 1 Answers
A few days ago
Favorite Answer
Work = Force x distance
Work = 50N x (10 cm * cos 60 degs)
= 50N x (10 cm * 1/2)
= 50N x (5 cm)
= 250 N-cm *** Note: “N-m” is a Joule, not N-cm ***
= 2.50 N-m
= 2.50 J
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