I need help with 2 math questions?
2) 30= 16+1/5x
The 1/5x is a fraction.
Favorite Answer
1) 10x-(-3x+5)=0
subtract the 10x from both sides : 10x -10x-(-3x+5)= -10x
then distribute the negative: 3x-5= -10x
then subtract the 3x from both sides : 3x-3x-5= -10x-3x
Then divide by 13: -5/13= -13x/13 (there fractions which means divide)
therefore x= – 5/13 (fraction) and thats your answer!
2) I’m gonna switch the order around so it looks better :16+ 1/5x =30
Now subtract 16 from both sides: 16-16+ 1/5x=30-16
Then 1/5x=14 so multiply by the reciprocal to both sides:
1/5 x * 5x=14*5
Therefore x= 70
2) 30 = 16 + 1/5x = 30 – 16 = 1/5x = 14 = 1/5x = 14 * 5 = x x = 70
10x +3x -5 (Distribute)
13x-5 (add like term.)
2) 30=16+1/5x
14=1/5x (Subtract 16 from both sides)
70=x (multiply by 5 to get rid of fraction)
10x – (-3x + 5) = 10x + 3x + 5 = 13x + 5
For the second, you can actually solve this so again, just collect like terms and solve for x.
30 = 16 + (1/5)x
14 = (1/5) x
5*14 = x
x = 70
To check, you can always plug back in to see 🙂
16 + (1/5)(70) = 16 + 14 = 30.
2) assuming its (1/5)x not 1/(5x), re-write as 14=(1/5)x. Multiplying both sides by 5 gives x=70.
10x + 3x -5
13x -5
30 = 16 + 1/(5x)
14 =1/(5x)
70x=1
x= (1/70)= 0.0142857
or
30 = 16 +(1/5)x
14 = (1/5)x
70=x
it depends on where the x is on which answer you need
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