graphing problem algebra HW help please?

x^3 + 5 = 4x^2 + 30x

how do you find out graphically how many solutions there are?

thanks =)

Top 1 Answers

A few days ago

Aquaboy

Favorite Answer

First, move all the terms to one side of the equation, (i.e. set the equation equal to zero), and then express the equation as, y in terms of x:

x^3 + 5 = 4x^2 + 30x

=> x^3 – 4x^2 – 30x + 5 = 0

=> f(x) = x^3 – 4x^2 – 30x + 5

=> y = x^3 – 4x^2 – 30x + 5

Now graph: y = x^3 – 4x^2 – 30x + 5.

The number of solutions for this equation, is the number of times the graph crosses the x-axis, (in this case, there should be 3 solutions).

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