A few days ago
first, write the value(s) that make the denominator(s) zero. Then solve the equation.?
x-6/3x + 2 = x+8/x
Top 2 Answers
A few days ago
Favorite Answer
The values of x that would make the denominators zero would be x=0.
To solve x – 6/(3x) + 2 = x + 8/x, first multiply through by the common denominator which is 3x.
3x^2 – 6 = 3x^2 + 24 This is not possible as you would get -6=24!!!! I’m thinking you must have left off some ().
Is it:
(x-6)/(3x+2) = (x+8)/x ??? If so, x = -2/3 also makes denominator zero. And to solve, multiply by x(3x+2):
x(x-6) = (x+8)(3x+2)
x^2 – 6x = 3x^2 +26x +16
2x^2 + 32x + 16 = 0
x^2 + 16 x + 8 = 0 Errr . . . this gives you complex answers. Well, I don’t know where the () should be in your problem, but neither of these works and I give up!
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A few days ago
x={3/8, -2/3}
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