A few days ago
find the third derivative where the second dervative is f”(x)=2-(2/x)?
please show work
Top 1 Answers
A few days ago
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first move the x variable to the top of the fraction using a negative exponent:
f”(x)=2-(2)(x^-1)
now just use the power rule for each term in the expression:
f”'(x)=0+(-2)(-1)(x^-2)
f”'(x)=2x^-2
f”'(x)=2/x^2
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