Find the equation of the line tangent to the graph of y = 5×3 – 2×2 + x + 3 at the point (-1,-5).?

Top 2 Answers

A few days ago

Anonymous

Favorite Answer

y = 5×3 – 2×2 + x + 3

y’ = 15x^2 – 4x + 1

When x = -1:

y’ = 15 + 4 + 1

= 20

The tangent is therefore:

y – (-5) = 20(x – (-1))

y + 5 = 20x + 20

y = 20x + 15.

4 years ago

Anonymous

keep in mind that the by-manufactured from a function is the SLOPE of the tangent line. so plug in pi/3 in y’= -sinx y’= -sin(pi/3) =sqrt(3)/2 ^slope of tangent line then plug in pi/3 into the unique equation to locate the y-coordinate of the element the place the tangent line touches the graph. y=cos(pi/3) y=a million/2 the equation of the tangent line in element-slope form could be: y – a million/2 = sqrt(3)/2 (x – pi/3) desire that enables!

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Find the equation of the line tangent to the graph of y = 5×3 – 2×2 + x + 3 at the point (-1,-5).?

Find the equation of the line tangent to the graph of y = 5×3 – 2×2 + x + 3 at the point (-1,-5).?

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