A few days ago
Find the derivative of f(x) = 1/x+1 at x=2 algebraically?
Find the derivative of f(x) = 1/x+1 at x=2 algebraically?
Top 5 Answers
A few days ago
Favorite Answer
if this is (1/x) +1, then f'(x) = -1/(x^2), and f'(2) = -1/4
if this is 1/(x+1), then f'(x) = -1/(x+1)^2, and f'(2) = -1/9
0
A few days ago
the answer for derivative of f(x) is f'(x) = -1/x^2..
when x=2, the answer would be f'(x)= -1/ 2^2 = -1/4
how to diffentiate it, basically, 1/x = x^-1. you bring the power in front, and the power on top of the unknown (x), being minus by 1…that’s result, -x^-2 = -1/x^2…
got it??
0
A few days ago
It depends, are you saying:
(1/x) + 1
or
1/(x+1)
—
If its (1/x)+1
The derivative would be – x^(-2)
Therefore it woudl be -1/4
—
If its 1/(x+1)
Then the derivative would be -1/(x+1)^2
The answer would be -1/9
0
A few days ago
f(x) = 1/x+1 , if x=2
so, f(2) = 1/2+1
f(2) = 1/3
0
A few days ago
f(x) = 1/x + 1
f(2) = 1/2 +1
f(2) = .5 + 1
f(2) = 1.5 when x = 2
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