A few days ago
Nextgen89

College Math Question, I need help, How many pounds of Italian coffe worth $5 per pound must be mixed with….

Okay heres the whole thing, If you cant help me out with an answer and work, I was hoping someone could give me the proper setup….

How many pounds of Italian coffe worth $5 per pound must be mixed with 20 pounds of Brazillian coffee worth $4 per pound to produce a mixture worth $4.20 per pound?

Top 3 Answers
A few days ago
Thee John Galt

Favorite Answer

You have:

Pi = price/lb of italian

Pb = price/lb of brazillian

Wi = weight of italian

Wb = weight of brazillain

Pm = price/lb of mix

Wm = weight of mix

Pi * Wi + Pb * Wb = Pm * Wm

The only variables we don’t know is Wi and Wm so we plug the other variables into the eq.

Wm is the total weight so we have:

Wm = Wi + Wb

Plug all the values we know plus that equation into the original eq and we get:

Pi * Wi + Pb * Wb = Pm * (Wi + Wb)

$5 * Wi + $4 * 20lbs = $4.20 * (Wi + 20lbs)

And now we solve for Wi

5 * Wi + 4 * 20 = 4.2 * (Wi + 20)

5 * Wi + 80 = 4.2 * Wi + 84

5 * Wi – 4.2 * Wi = 4

0.8 * Wi = 4

Wi = 5

So you would need 5lbs of Italian roast.

1

A few days ago
cincykt
1) Define variable:

i = # pounds of Italian coffee

2) Write equation:

** For each term (Italian, Brazillian, & mixture), multiply the amount of that type you have by the price of the type to get how much that type is worth.

** Note that you have 20 + i pounds of the blend

5i + 4 ( 20) = 4.20 ( 20 + i)

3) Solve

5i + 80 = 84 + 4.20i

.80i = 4

i = 5 pounds

1

4 years ago
oppie
x stands for $6 tea y for $8 tea remedy simulationously, x+y=a hundred and forty four (6x+8y)/a hundred and forty four = 7.5 so simplify the 2d equation 6x + 8y = 1080 3x +4y = 540 now we are able to remedy via removing 3x +4y = 540 3x + 3y =432 (multiply the 1st equation via 3) we get y = 108 for this reason x=36 that’s, 36 pounds of $6 tea and 108 pounds of $8 tea to make a hundred and forty four pounds of $7.50 tea
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