College Math Question, I need help, How many pounds of Italian coffe worth $5 per pound must be mixed with….
How many pounds of Italian coffe worth $5 per pound must be mixed with 20 pounds of Brazillian coffee worth $4 per pound to produce a mixture worth $4.20 per pound?
Favorite Answer
Pi = price/lb of italian
Pb = price/lb of brazillian
Wi = weight of italian
Wb = weight of brazillain
Pm = price/lb of mix
Wm = weight of mix
Pi * Wi + Pb * Wb = Pm * Wm
The only variables we don’t know is Wi and Wm so we plug the other variables into the eq.
Wm is the total weight so we have:
Wm = Wi + Wb
Plug all the values we know plus that equation into the original eq and we get:
Pi * Wi + Pb * Wb = Pm * (Wi + Wb)
$5 * Wi + $4 * 20lbs = $4.20 * (Wi + 20lbs)
And now we solve for Wi
5 * Wi + 4 * 20 = 4.2 * (Wi + 20)
5 * Wi + 80 = 4.2 * Wi + 84
5 * Wi – 4.2 * Wi = 4
0.8 * Wi = 4
Wi = 5
So you would need 5lbs of Italian roast.
i = # pounds of Italian coffee
2) Write equation:
** For each term (Italian, Brazillian, & mixture), multiply the amount of that type you have by the price of the type to get how much that type is worth.
** Note that you have 20 + i pounds of the blend
5i + 4 ( 20) = 4.20 ( 20 + i)
3) Solve
5i + 80 = 84 + 4.20i
.80i = 4
i = 5 pounds
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