1) OK, the density is 1.50 g/ml. In other words, if you had enough liquid to have 1.50 g of it (or 1500 mg), it would take up 1 ml of space. Now, you only have 3.00 mg. How much would you have to multiply your 3 mg by to make it 1500 mg? Since density is a ratio, you’d have to multiply the volume that your 3 mg take up by the SAME number to get 1 ml. Use that information to find out how many ml of liquid you have. Convert that to liters and use a liters to gallon conversion (if you don’t have one already, try here: http://www.calculateme.com/Volume/index.htm) to get gallons.

Hint: your answer is REALLY small (on the order of 10^-7)

2) You need .5 kg of red cells. How many grams is that? I’ll call it x. You know the density of one red blood cell is 1.096 g per ml. So if you had x grams of cells, how much volume would that take (how many ml)? Now that you know the total volume of red cells you need, divide that by the volume of a single red cell (remember that cm^3 is the same as a ml) to get the NUMBER of red cells you would need to get that volume. Now you know the total number of red cells you need to have. Use the given data on the number of red cells per ml of blood to find out how many ml of blood you need. Then convert that to liters to get your answer.

3) The volume of a cylindrical drum is the area of the circular base * the height of the cylinder. You know the formula for finding the area of a circle with a given radius. For now, multiply that by h, which stands for your unknown height in feet. This is your cylindrical volume expression.

You know that the volume of water is 1 kg/liter, so you can figure out what volume 2000 kg of water would take up.

The volume of water is equal to the volume of the cylinder filled to unknown height h. Solve for h, remembering that the cylindrical volume expression is in cubic feet while your water volume expression is in liters, so you’ll need a conversion.

4) If the density of silver is 10.5 g/ml and you have 194.3 g, you can figure out how much space your silver takes up (i.e., how many ml of silver you have). Add the volume of silver to the volume of water to get the final volume displayed by the graduated cylinder.

The GMW of hydogen is a million so as meaning that there is 29 g of Cl in the given volume of HCl. you spot that a million/2 of the Cl is utilized in MnCl2 so, consequently, a million/2 of the Cl is in the gasoline Cl2. Your answer is d) 14.6g.