Can you solve the system using any algebraic method? please hurry!!?
b. x+y-z=7, 2x-3y+z=2, 4x+2y-2z=20
Favorite Answer
First, get one variable all by itself
-5x-y=3 (add y to both sides)
-5x=y+3 (subtract 3 from both sides)
-5x-3=y
Now, let’s look at the second equation
x-4y=9 (now, we said earlier that y=-5x-3)
x-4(-5x-3)=9 (multiply everything out)
x+20x+12=9 (combine all x’s)
21x+12=9 (subtract 12 from both sides)
21x=-3 (divide both sides by 21)
x=-3/21
now that we know the value of x, let’s re-evaluate our first equation.
-5x-y=3 (we know x=-3/21)
-5(-3/21)-y=3
15/21-y=3 (add y to both sides)
15/21=y+3 (subtract 3 from both sides)
-6/21=y
Now, go solve B
-3/21=-1/7, -6/21=-2/7
-5x-y=3
-5(-1/7)-(-2/7) is not equal to 3
5/7+2/7=1, not 3
since jack got the y=-16/7, then i calculate the x = -1/7, lets check
-5x-y=3
-5( -1/7)-(-16/7)=3
5/7+16/7=3
21/7=3
3=3
lets check x-4y=9
( -1/7)-4(-16/7)=9
( -1/7)+64/7=9
63/7=9
x-4y=9
lets pick x-4y=9, then x=9+4y
substitute to the 1st equation
-5x-y=3
-5(9+4y)-y=3, since we know the x is 9+4y
-45-20y-y=3
-20y-y=3+45
-21y=48
y= -16/7
you should know how to find x now since you know the value of y
now you got the idea, try to solve the 2nd one yourself.
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