A few days ago
I’mReallyJustAskingToLeave

Can two parenthesis be right by each other, or does it have to be a bracket?

I am starting pre-algerbra in my 6th grade class, and I need your help. Here is the problem, I can’t skip any steps or do shortcuts to solve it.

3[6(12-3)] -17

Here is the part I am stuck on. Once I subtract 12-3 (parenthesis first) what do I do with the brackets? Leave them or change them into parenthesis?

Top 5 Answers
A few days ago
anonymous

Favorite Answer

Brackets are functionally equivalent to parentheses. They have to match though . . . [2) is not a valid expression. You simplify by going from the innermost expression to the outermost. For example:

[([((5+1)*2)/2]+1)+17]

=[([(6*2)/2]+1)+17]

=[([12/2]+1)+17]

=[(6+1)+17]

=[7+17]

=24

Good night!

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A few days ago
marcopolo
parenthesis first then do whats inside the brackets so

so 12-3=9

3[6(9)]-17

3[54]-17

the brackets around the 54 mean nothing. the only way you would use them is if you have a negative number. if you had a negative number you would just change it to make it positive.

162-17

145

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A few days ago
Anonymous
What do you mean? ..

First you subtract 12 from 3. Then, you multiply 6 to your answer.

After, you multiply 3 to your answer. Finally, take your answer and subtract 17 from it.

12 – 3 = 9

6 * 9 = 54

54 * 3 = 162

162 – 17 = 145

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A few days ago
Leah D
first subtract 12 and 3, then multiply that by 6, then multiply that answer by 3, and subtract 17
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A few days ago
♥italianbaby12♥
do the parenthesis first and then do the brackets

it would be like this

3[6(12-3)] -17

3[54] -17

162-17

145

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