A few days ago
can someone please help with derivative of trig functions?
I know this probably an easy problem, but I have no idea how to start it.
4cos(sinx)
Can someone please help me?
Top 1 Answers
A few days ago
Favorite Answer
y = 4cos(sin(x))
Using the chain rule:
dy/dx = – 4 sin(sin(x)) (d/dx)(sin(x))
= -4 sin(sin(x)) cos(x).
y = -2csc(9x)
dy/dx = 2 cot(9x)cosec(9x) (d/dx)(9x)
= 18cot(9x)cosec(9x).
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