A few days ago
Can someone please help me solve this really short chemistry calculation?
You have a 200.0 mL graduated cylinder containing 58.3 mL of water. A piece of metal with a density of 12.40 g/cm3 weighing 50.00 g is placed in the cylinder. What is the reading on the cylinder after the metal has been added?
Please, any sort of help is greatly appreciated. I tried it many different way. I know I have to use V=m/d.
Please help anytime you feel like it.
Top 1 Answers
A few days ago
Favorite Answer
The volume of the metal is:
(50.00gm) / (12.40gm/cm^3)
= 4.032cm^3
= 4.032ml.
The new reading on the cylinder is therefore:
58.3 + 4.032
= 62.3 ml. to nearest 0.1ml.
0
- Academic Writing
- Accounting
- Anthropology
- Article
- Blog
- Business
- Career
- Case Study
- Critical Thinking
- Culture
- Dissertation
- Education
- Education Questions
- Essay Tips
- Essay Writing
- Finance
- Free Essay Samples
- Free Essay Templates
- Free Essay Topics
- Health
- History
- Human Resources
- Law
- Literature
- Management
- Marketing
- Nursing
- other
- Politics
- Problem Solving
- Psychology
- Report
- Research Paper
- Review Writing
- Social Issues
- Speech Writing
- Term Paper
- Thesis Writing
- Writing Styles