3(-2-3x)=9x-4

First distribute the 3.

-6-9x=9x-4

Second put like terms together. What you do to one side of the equal sign you must do to the other side.

-6+6-9x-9x=9x-9x-4+6

-18x=2

Now divide both sides by -18.

(-18x)/-18=2/-18

x=2/-18=1/-9

Good luck on the rest.

ex. 3 (d-8) – 5 = 9 (d + 2) + 1

3d-24-5=9d+18+1

When you have a number outside of a parenthetical expression, you multiply both terms by that number:

3(-2-3x)

First, 3 * -2 = -6

Then, 3 * -3x = -6x

So, 3(-2-3x)= -6 – 6x . . . get it?

So for the first problem:

-6 – 6x = -9x -4

Then you need to get variables to one side (the x’s) and the whole numbers to the other:

So let’s add +6x to both sides to get rid of it on the left side:

-6x + 6x = 0 (left side)

-9x + 6x = -3x (right side)

Now, on let’s add +4 to both sides:

-6 + 4 = -2 (left side)

-4 + 4 = 0 (right side)

So what we’re left with is

-3x = -2

Now divide the coefficient -3 through (because we want to get x by itself) on both sides and we get:

x = 2/3

Hope this helped!