Can anyone figure out a formula for this it should be simple. Its that +1 formula. Heres the In and Out table?
1 2
2 4
3 7
4 11
5 16
Favorite Answer
theres no geometric pattern here so you want to find a pattern where some kind of (n+1) or n-1 leaves you with a remainder that gives you a nice geometric pattern
if you work at you’ll end up looking at [(n+1)^2]/2
now if you try that you’ll get
n=1 [(1+1)^2]/2 = 2 – 0
n=2 [(2+1)^2]/2 = 4.5 – .5
and so on n=3 = 8 – 1
n=4 = 12.5-1.5
n=5 = 18 – 2
so looking at the remainders theres a pattern of -n/2 + 1/2
so in the end you get a formula of [(n+1)^2]/2 -n/2 + 1/2
and if you do some factoring you are left with (n^2 + n +2)/2
far from simple but it works =p
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