can anybody help me with a few algebra 2 questions? plz im desperate!!?
2. Find an equation in standard form for the line parallel to the x axis with a y-intercept of 6.
3. Solve the following system of equations:
2y + 3x = 1
-7x – 5y = -4
4. Solve the following system of equations:
y = 2 – 6×1 y – 6 = 1
2
5. Solve the following system of equations:
2x – 3y = 2 – x
3x – 2y = -2 + y
If there is no solution, type “no solution”. If there is not enough information present to solve the problem, type “not enough information”. thank you you saved me from a heap of trouble.
Favorite Answer
First, find the slope:
m = (4 – 4) / (-3 – 1) = 0 / -4 = 0
Then write the equation using one point and the slope.
y – 4 = 0(x – 1)
y – 4 = 0
y = 4
2.
Any line parallel to the x-axis has an equation in the form
y = #
Since the y-intercept is 6, your equation is
y = 6
3. Solve the following system of equations:
#1: 2y + 3x = 1
#2: -7x – 5y = -4
Solve one equation for one variable. (I’ll solve #1 for y)
2y + 3x = 1
2y = 1 – 3x
y = (1 – 3x) / 2
Now put that in the other equation and solve for the other variable.
-7x – 5y = -4
-7x – 5[(1-3x)/2] = -4
(Multiply everything by 2 to eliminate fraction)
-14x – 5(1 – 3x) = -8
-14x – 5 + 15x = -8
x – 5 = -8
x = -3
Now put that back into either equation to solve for the missing variable.
2y + 3x = 1
2y + 3(-3) = 1
2y – 9 = 1
2y = 10
y = 5
4.
I can’t understand your equations. But you’ve seen how to do #3, so you should be able to at least TRY #4 yourself.
5.
First, simplify both equations
#1: 2x – 3y = 2 – x
3x – 3y = 2
#2: 3x – 2y = -2 + y
3x – 3y = -2
Notice that both equations are identical on the left side, but different on the right.
That means there is “no solution” – these are two parallel lines, so they will never intersect.
1. x=4
2. y=6
3. {x=13, y=-19}
4. uhm…. i kinda didn’t get the problem :p it’s kinda vague…
5. there’s no solution… x’s and y’s cancel each other…
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