Average Velocity?
40t – 16t^2. for the time period beggining when t = 2 and lasting ,.5 s ,.1 s, .005 etc
I was able to find .5 s by plugging in (40(.5) – 16(.5^)2)/-.5 = -32 ft/s….However when I tried to do the same thing with the other (.1) I got an answer of -38.4 f/t, when I check my answer in the back of the book, its supposed to be -25.6 ft/s
Could anyone tell me the correct way to do this problem, its confusing because I got it right for the 1st time interval, but I cant for the others, using the same method.
Favorite Answer
you need to find the velocity at:
t = 2.0 sec
t=2.5
t=2.1
t=2.005
add v(2) and v(2.1) and divide by 2 to get the average.
I THINK YOU ARE ACTUALLY TRYING TO FIND THE AVERAGE ACCELERATION???????
AVE ACCEL = (v,final – v,initial)/(t,final-t,initial)
1st time interval
a,ave = [ v(2.5) – v(2.0)] / (2.5-2.0)
= [ 0 – 16 ] / (0.5) = -32 ft/s^2
2nd time interval
a,ave = [ v(2.1) – v(2.0)] / (2.5-2.0)
= [ 13.44 -16 ] / (0.1) =
= [-2.56]/0.1 = -25.6 ft/s^2
what you are doing is finding
v(0.5)/(-0.5)
v(0.1)/(-0.1)
you are just finding the velocity at a certain time, and dividing it by that time. you are not finding the change in velocity over that time, starting at t=2.0.
v(0.5) just happens to be 16 … you get a right answer, even though your physics/math is not correct.
an unfortunate problem set-up.
good luck
- Academic Writing
- Accounting
- Anthropology
- Article
- Blog
- Business
- Career
- Case Study
- Critical Thinking
- Culture
- Dissertation
- Education
- Education Questions
- Essay Tips
- Essay Writing
- Finance
- Free Essay Samples
- Free Essay Templates
- Free Essay Topics
- Health
- History
- Human Resources
- Law
- Literature
- Management
- Marketing
- Nursing
- other
- Politics
- Problem Solving
- Psychology
- Report
- Research Paper
- Review Writing
- Social Issues
- Speech Writing
- Term Paper
- Thesis Writing
- Writing Styles