A few days ago
Anyone wanna take a shot at this Algebra question?
Two trains are 240 miles apart traveling torward each other on parallel tracks. One travels at 35 mph and the other at 45 mph. At the front of the faster train is a bee that can fly 75 mph. The bee flies from one train to the other until the trains pass each other. When the trains pass, how far has the bee flown?
Top 3 Answers
A few days ago
Favorite Answer
225 miles
0
A few days ago
That is one fast bee!
r*t=d
the time for both is the same when they pass.
r1/d1 = r2/d2
d1+d2=240
35/d1=45/d2
or 35*d2=45*d1
or
d1 = 35/45 * d2
d1 = 7/9 d2
d1 + d2 =240
7/9*d2 + d2 = 240
7*d2 + 9*d2 = 240(9)
16*d2 = 240(9)
d2=240(9)/16 = 15*9 = 90
from above r2=45
r2*t=d2
45*t=90
t=2 hours
that fast bee is moving at 75 mph
r*t=d
75(2) = d
150 miles
0
A few days ago
I haven’t done this in awhile so please try to verify.
(R1*T1)+(R2+T2)=distance
R1=35 MPH
R2=45MPH
35T1+45T2=240
Now both trains started at the same time
so T1=T2
35T+45T=240
80T=240
T=3;
So the total is 3 hours until the trains meet each other.
3*75MPH=225 miles
0
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