A few days ago
An Algerbra II Question?
The quest itself is very confusing, let me read it for you:
Write an equation of the line that passes through the given point and satisfies the give condition.
(-2,3); Parallel to y=4x-3
Does anyone knows what I am supposed to write?
Top 4 Answers
A few days ago
Favorite Answer
parallel lines always have the same slope. so you know the other line will have a slope of 4 (m=4). now you take the point (-2,3) and plug it into the equation y=mx+b to find b.
slope=4
y=3
x=-2
so……. 3=4(-2)+b
b=11
then take m and b and put it back into the form y=mx+b
y=4x+11
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A few days ago
You have to write an equation that goes through the point -2, 3 and is parrallel to y=4x+3
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A few days ago
well m=4(cause its parellel)
so then you write out the point slope formula, which is
y-y1=m(x-x1)
plug in points and slope.
y-3=4(x+2)
distribute 4(x+2)=4x+8
so then you have
y-3=4x+8
add 3
y=4x+11 thats your answer.
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A few days ago
it’s either
a.] y= 4x+11
or
b.]y = -3x-3
I’m just to lazy to graph it,
so I’m not so sure about the answers
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