Algebra question? Easy ten points?
a.) 3x – 4 = 2y – 2
b.) 8 = 2/3xyz
c.) m/3 + 6 = n/2
I think it’s the variables that confuse me the most… Thanks.
Favorite Answer
Step2 [divide by 2]: (3x-2)/2=y
b) Step1[divide each side by 2/3]: 12=xyz
Step2 [now divide by xz]: 12/xz=y
c) I didn’t know what variable you are solving for since there’s no y so sorry, I solved for both n&m.
Step1 [multiply by 2]: 2m/3 + 12 = n
if solving for m…
Step1 [subtract 6 from both sides]: m/3 = n/2 – 6
Step2 [multiply by 3]: m = 3n/2 – 18
3x – 4 = 2y – 2
+2 +2
———————
3x – 4 + 2 = 2y <-doing that it cancels out the 2 on the right ------------- ---- 2 2 3x - 4 + 2 = y ------------- 2 b) You have to divide both sides by 2/3xz to get y by itself and since you can't have a fraction in a fraction you have get rid of 2/3 by multiplying my 3/2 8 = 2/3xyz --- --------- 2/3xz 2/3xz 8 = y --- 2/3xz (3/2) * 8 ------------ = y 2/3xz 12 ----- = y xz c) m n --- + 6 + --- (what are solving for?) 3 2
3x-4+2=2y
(3x+6)/2=y
b) 8=2/3xyz
12.0012=xyz
(12.0012)/x=yz
((12.0012/x)/z)
c) m/3+6=n/2
2(m/3 +6)=n
It is very easy to understand
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