A few days ago
Precalculus problem?
A hot-air balloon, headed due east at an average speed of 6 miles per hour and at a constant altitude of 190 feet,
passes over an intersection . Find an expression for the distance D (measured in feet)
from the balloon to the intersection T seconds later.
Top 2 Answers
A few days ago
Favorite Answer
6 mph = 31680 feet/3600 sec = 8.8 feet second
so in T seconds, horizontal distance = 8.8T
D is the hypothenuse of the triangle formed by the 8.8t and the 190 feet altitude = sqrt(190^2 + [8.8T]^2) = sqrt(36100 + 77.44T^2)
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A few days ago
^
|
———|——- > 6 m/hr
|
| 190 nfeet
speed = dist / time
6m/hr = D / T
D = 6 T
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