A few days ago

baowy

Algebra but actually chemistry either way.?

Ok for chemistry we are given these equations and are told to get each variable by itself.

For ex:

a=c+b

c=a-b

b=a-c

Now for my question, now i want to how to solve for each variable with this equation,

w=P(Vf-Vi)+1/2mv^2

but im not sure how to do it.

Also Vf and Vi are 1 variable not separate variables like V and f.

Some help please?

Top 1 Answers

A few days ago

bedbye

Favorite Answer

W=P(Vf-Vi)+½mv²

Solving for P, Vf, and Vi:

W – ½mv² = P(Vf-Vi) ***

[W – ½mv²]/(Vf-Vi) = P

P=[W – ½mv²]/(Vf-Vi)

W – ½mv² = P(Vf-Vi) ***

[W – ½mv²]/P = (Vf-Vi) ~~~

[W – ½mv²]/P + Vi = Vf

Vf = [W – ½mv²]/P + Vi

and

[W – ½mv²]/P = (Vf-Vi) ~~~

-Vi = [W – ½mv²]/P -Vf

Vi = Vf – [W – ½mv²]/P

Solving for m & v:

W – ½mv² = P(Vf-Vi) ***

– ½mv² = P(Vf-Vi) – W

½mv² = W – P(Vf-Vi)

mv² = 2[W – P(Vf-Vi)]

m = (2/v²)[W – P(Vf-Vi)]

and

mv² = 2[W – P(Vf-Vi)]

v² = (2/m)[W – P(Vf-Vi)]

v = √{(2/m)[W – P(Vf-Vi)]}

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