A few days ago
Algebra 2 q’s?
1. (5a^4b^-2c^3)^-2
= (25b^4)/(a^8c^6) ?
2. [(24x^-2y^4)/(8xy^2)]^-3
= ? i got (-27x^27)/(y^8)
but it was marked wrong
help, thanks!:))
Top 4 Answers
A few days ago
Favorite Answer
First get rid of the negative exponent for b, by moving that to the denominator. Then take that entire fraction and put it under 1 to remove the -2. Square the denominator (fraction) The answer should be:
(b^4) / (25 a^8 c^6)
Sorry, I didn’t see the -2 on the b in the original problem.
1
A few days ago
(5a^4b^-2c^3)^-2
are you missing something in that equation?
(5a^4+b^-2c^3)^-2 or perhaps (5a^4-b^-2c^3)^-2 ?
b.
[(24x^-2y^4)/(8xy^2)]^-3
again, I think you might have typed the problem incorrectly.
to what power is the x raised? if -2, then is y added or substract? If -2y^4, I think you are beyond simplifying the equation.
please proofread and repost.
0
A few days ago
1. -25a^-8b^4c^-6
2. Unsure, sorry.
0
A few days ago
im bad at math
0
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