A few days ago
mica! mica mica

Algebra 2 Help!!! pleese………..?

Jimmy has $5.00 in nickels, dimes, and quarters. He has the same amount of quarters as dimes. If he has 50 coins in all, how many of each does Jimmy have?

Top 3 Answers
A few days ago
jsardi56

Favorite Answer

Let x == the number of quarters

x is also the number of dimes

Let n = the number of nickels

We need to set up two equations:

Number of coins:

x + x + n = 50

2x + n = 50

n = 50 – 2x

Total of the money:

25x + 10x + 5n = 500

Substitute for n in the second equation:

35x + 5(50 – 2x) = 500

35x + 250 – 10x = 500

25x = 250

x = 10 dimes and 10 quarters

n = 50 – 2x

n = 50 – 2(10)

n = 50 -20 = 30 nickels

1

A few days ago
Toklioko
ok, this was a hard question, but you’ve got to try using diff numbers. It says that you’ve got the same amount of dimes and quarters. Plus you have a total of 50 coins.

so lets try 15 dimes, 15 quarters and 20 nickels:

15x10cents= 1.50

15x25cents=3.75

20x5cents=1

Total: $6.25

If the amount is too high you’ve got to lower the amount of dimes and quarters.

here’s the answer:

10 dimes, 10 quarters, and 30 nickels

I hope you understood the question:)

0

A few days ago
Gibran S
im not sure
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