A few days ago
alg2 help!!?
1. Paula’s purse contains twice as many dimes as quarters and three fewer nickels than dimes. The total of these coins in 3.15
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A few days ago
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I always tell my students that it’s best to make the second item mentioned in a comparison be equal to x. The other items mentioned can then be written in terms of x.
dimes = 2x (twice as many dimes as quarters)
quarters = x
nickels = 2x – 3 (three fewer nickels than dimes)
You need to multiply the number of each coin times its value.
.10(2x) + .25(x) + .05(2x – 3) = 3.15 multiply
.20x + .25x + .10x – .15 = 3.15 add similar terms
.55x – .15 = 3.15 add .15 to each side
.55x = 3.30 divide by .55
x = 6 now find the other coins
dimes = 2x = 2(6) = 12
quarters = x = 6
nickels = 2x – 3 = 2(6) – 3 = 9
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