A few days ago
a motorboat can go 18mph in still water. if a trip dowstream takes 4 hours and the return trip takes 5 hours.?
find the speed of the current.
Top 1 Answers
A few days ago
Favorite Answer
Good question! – I had to scratch my head on this one…
Distance = Rate * Time
Distance = (Rate of boat ± speed of the current) * Time
Let x = speed of the current
Distance downstream = (18 mph + x) * 4 hours
Distance upstream = (18 mph – x) * 5 hours
In this case, the distances are equal for both trips,
so we can set both equations equal to one another.
(18 mph + x) * 4 hours = (18 mph – x) * 5 hours
72 mph + 4x = 90 mph – 5x
4x + 5x = 90 mph – 72 mph
9x = 18 mph
x = 2 mph
So, the speed of the current is 2 miles per hour.
Good luck in your studies,
~ Mitch ~
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