A few days ago
Anonymous

6x+4y= -12 8x-14y= -16?

using substitution….?

i need to know step by step how to do it not just the answers..

i want to learn this..

Top 4 Answers
A few days ago
Anonymous

Favorite Answer

The following steps should help you understand how to solve this type of question by substitution.

1. Firstly, you need solve one of the equation for one of the variables. So:

6x +4y = -12 solving for y it becomes

4y = -6x – 12, then

y = 1/4 (-6x – 12) or y = – 3/2 x – 3

Now, we must then insert y = – 3/2 x – 3 into the other equation

8x -14y = -16 becomes

8x -14 (- 3/2 x – 3) = -16 or multiplying the bracket by -14 gives:

21x + 42 +8x = -16, or adding 21x and 8x gives

29x + 42 = -16, then subtracting 42 from both sides gives

29x = -58 which simplifies to

x = -2.

Now substitute x = -2 into y = – 3/2 x – 3 to get

y = (-3/2) (-2) – 3, or

y = 3 – 3 or y = 0

So your answers are x = -2 and y = 0

Sorry it’s so long, hope this helps ๐Ÿ™‚

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A few days ago
Orfeas
6x+4y=12 } 6x=12-4y } x=12/6-4/6y } x=2-2/3y }

8x-14y=-16} 8x-14y=-16 } 8x-14y=-16 }8(2-2/3y)-14y=-16 }

x=2-2/3y } x=2-2/3y } x=2-2/3y } x=2+2*96

16-16/3y-14y=-16 |3*} 48-16y-42y=-48 } -58y=48+48} y=-96/58

x=2+2*96/3*58 } x= 2+192/174 } x=2+96/87 } x=270/87

y=-96/58 } y=-48/29 } y=-48/29 }y=-48/29

*this means multiply everything by 3 so that 16/3 becomes 16

I wrote as simply as i could so you can understand it. The method is right, i don’t know if i missed something in a multiplication.

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A few days ago
tomdawg ใƒ„
Okay so in one of the equations, substitute 0 in for x to solve for y, then use y to find the correct x.

6x+4y=-12

6(0)+4y=-12

0+4y=-12

0-0+4y=-12-0

4y=-12

y=-3

6x+4(-3)=-12

6x-12=-12

6x=12-12=12-12

6x=0

x=0

y=-3 and x=0…

6(0)+4(-3)=-12

0-12=-12

-12=-12

and do the same process for the other one

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A few days ago
e257rage
sorry , the anser is x = -2 , y = 0 . I haven’t done this for nearly 20 years , done it in my head through quick estimation and trial and error but couldn’t tell you how you write it down , hope it helps a bit.
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