A few days ago
(-3,0),y=2/3x +1?
write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of each equation.
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A few days ago
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y = (2/3)x + 1 is in slope-intercept form. Any linear equation of the form y = something is in slope-intercept form, as long as there are no y’s in the “something”. Slope-intercept form is
y = mx + b
where m is the slope. So, whatever’s multiplying the x is the slope. In this case, that’s 2/3.
Now – two parallel lines must have the same slope. So, any line parallel to this one will be of the form
y = (2/3)x + b
All that will change, and all you have to find, is the b. You do that by plugging in the point you have:
0 = (2/3)*(-3) + b
0 = -2 + b
b = 2
So the line parallel to y = (2/3)x + 1 passing through (-3, 0) is
y = (2/3)x + 2
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