A few days ago
thisisjakethomas

# logs?????????????

what is 3logx+4log(x-2) written as a single logarithim?

please tell me step by step…I am soooo confused

A few days ago
Anonymous

I’ll tell you what is is: OMG
0

A few days ago
Anonymous
the 3 and 4 go up on each as exponents, because the exponent on a log can be written in front as a coefficient… so it would be written (logx)^3 + (log(x-2))^4

when you add logs (logx+logx-2) you are actually multiplying them in parentheses… dividing means that you are subtracting them…

So you would get log(x^3(x-2)^4)

I would assume that you can leave it like this, considering that (x-2) to the fourth would take a little while to multiply out.

logs are very confusing, and not fun at all!

Hope I could help!

0

A few days ago
championsk8r
you can change 3logx into log(x)^3 and 4log(x-2) into log(x-2)^4. since theyr adding the logs and they have the same base, you can change it to log((x^3)(x-2)^4). idk if your teacher wants you to simplify everything in the log further, but you would just multiply it out and combine like terms.. hope that helped!!
0