Frequency Distribution
Frequency distribution:
The table below contains data collected:
DATE
MINUTES TO DRIVE TO WORK
MON/5 OCT
30 MIN
TUES/6 OCT
30 MIN
WED/7 OCT
1/12
Frequency Distribution
20 MIN
THURS/8 OCT
20 MIN
FRI/9 OCT
SICK LEAVE/DID NOT GO TO WORK
MON/12 OCT
COLUMBUS DAY/DID NOT GO TO WORK
TUES/13 OCT
SICK LEAVE/DID NOT GO TO WORK
WED/14 OCT
SICK LEAVE/DID NOT GO TO WORK
2/12
Frequency Distribution
THURS/15 OCT
SICK LEAVE/DID NOT GO TO WORK
FRI/16 OCT
SICK LEAVE/DID NOT GO TO WORK
We assume that for the days that the individual did not report to work the minutes taken to drive to work amount to zero, therefore the table is summarized as follows:
DATE
MINUTES TO DRIVE TO WORK
MON/5 OCT
30 MIN
3/12
Frequency Distribution
TUES/6 OCT
30 MIN
WED/7 OCT
20 MIN
THURS/8 OCT
20 MIN
FRI/9 OCT
0
MON/12 OCT
0
4/12
Frequency Distribution
TUES/13 OCT
0
WED/14 OCT
0
THURS/15 OCT
0
FRI/16 OCT
0
The frequency distribution table will contain three classes and they include the class 0 to 10, 11 to 21 and 22 to 32, the table below summarizes the frequencies:
5/12
Frequency Distribution
class
frequency
0 to 10
6
11 to 21
2
22 to 32
2
total
10
6/12
Frequency Distribution
Standard deviation:
The standard deviation for grouped data is calculated as follows:
Sd = [(FX2/ f) – (FX/F)2]½
The table below summarizes the midpoints of the classes and calculations made to determine the standard deviation:
x
class
Frequency(FX)
7/12
Frequency Distribution
mid point
FX
FX2
0 to 10
6
5
30
900
11 to 21
2
16
8/12
Frequency Distribution
32
1024
22 to 32
2
27
54
2916
total
10
116
9/12
Frequency Distribution
4840
Given
Sd = [(FX2/ f) – (FX/F)2]½
Then
Sd = [(4840/ 10) – (116/10)2]½
Sd = 18.69331
Normal distribution:
The central limit theorem givens the conditions and properties of a normal distribution, they include:
68% of data is contained within one standard deviation, 95% of the data is contained within two standard deviations, the mean value is determined as follows:
Mean = FX/F
10/12
Frequency Distribution
Mean = 116/ 10 = 11.6
68% of observations:
Standard deviation = 18.69331
Mean = 11.6
Range of data
(11.6+ 18.69331) and (1.6 – 18.69331)
(30.29331) and (-7.09331)
From our case data that ranged from -7.09331 to 30.29331 is greater than 68%, therefore the distribution is not a normal distribution.
Implications:
Given that this is not a normal distribution this means that statistical tests that assume normal
11/12
Frequency Distribution
distribution cannot be applied, also this means that the sample is not large enough given that the central limit theorem states that as the number of random numbers increase the data assumes a normal distribution.
REFERENCE:
Mendenhall, W. (2003) Introduction to statistics, Prentice Hall press, New Jersey
12/12
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