A few days ago
miss s

# help algebra please! dont give answer just show me the equation with variable?

You have to solve the equation with shown variable

The attendance of the game is 400 people.student tics. are \$2 each. Adult tics. cost \$3 each.Total money made was \$1050.How many tickets of each were sold?

A few days ago
nats..

x= students

2x + 3y = 1050

x + y = 400

2x + 3y = 1050

– 2x + 2y = 800

= y = 250

x + 250 = 400

x = 150

there were 250 adults and 150 students

0

4 years ago
?
you get 3 equations: a million) 4x + 6y – 3z = 20 2) x – 5y + z = 15 3) -7x + y + 2z = a million and you have 3 variables. What i might do, is substitute between the variables in the different 2 equations, i’ll do this with z. by potential of doing this, you get to new equations to get x and y, that’s plenty much less complicated because it is straightforward. i’ll get the value of z in equation 2) so: 2) x – 5y + z = 15 subtract x -5y + z = 15 – x upload 5y z=15 – x + 5y Now I replace z in the different 2 equations. So: a million) 4x + 6y – 3z = 20 replace z 4x + 6y – 3(15 – x + 5y) = 20 so: 4x + 6y – 40 5 + 3x – 15y = 20 upload equivalent matters 7x – 9y – 40 5 = 20 upload 40 5 7x-9y=sixty 5 this may well be now equation 4) now I replace z in equation 3) so: 3) -7x + y + 2z = a million replace z -7x + y + 2(15 – x + 5y) = a million so: -7x + y + 30 – 2x + 10y = a million upload equivalent matters -9x + 11y + 30 = a million subtract 30 -9x + 11y = -29 this may well be equation 5) So, doing an equation device between equation 4 and 5 4) 7x-9y=sixty 5 5) -9x + 11y = -29 i’ll substitute the subject of the two equations to x equals to a minimum of something to get the value of y so: 4) 7x – 9y = sixty 5 upload 9y 7x=sixty 5+9y divide by potential of seven x=(sixty 5+9y)/7 5) -9x + 11y = -29 upload 9x 11y = -29 + 9x upload 29 11y + 29 = 9x divide by potential of 9 (11y + 29)/9=x for this reason: (11y + 29)/9=(sixty 5+9y)/7 multiply by potential of 9 11y + 29 = 9(sixty 5+9y)/7 multiply by potential of seven 7(11y + 29)=9(sixty 5+9y) for this reason: 77y + 203 = 585+81y subtract 77y 203 = 585 + 4y subtract 585 -382=4y divide by potential of four -ninety 5.5 = y cool, we’ve y then we replace y in equation 4) to get x so: 4) x=(sixty 5+9y)/7 x=(sixty 5 + 9*-ninety 5.5)/7 x=(sixty 5 – 859.5)/7 x=-794.7/7 x=-113.5 so we’ve x=-113.5 and y=-ninety 5.5 we now replace the two values on equation 2) so: 2) x – 5y + z = 15 -113.5 – 5*-ninety 5.5 + z = 15 -113.5 + 477.5 + z = 15 364 + z = 15 subtract 364 z = -349 so we’ve: x=-113.5, y=-ninety 5.5 and z = -349 so: (x, y, z) (-113.5, -ninety 5.5, -349)
0

A few days ago
Anonymous
ok you need 2 equations.

A (adults) + S (students) = 400

3A + 2S = 1050

Then you solve for A and for S

0

A few days ago
mesprit
i just did it through trial and error there where 150 sudents and 250 adults sorry i cant give you a better answer
0

A few days ago
pol_224
well the equation would look like:

2s + 3a = 1050

thats what i believe. if thats correct, than you have to guess and check.

0