1 – I

2 – II

3 – III

4 – IV

5 – V

6 – VI

7 – VII

8 – VIII

9 – IX

10 – X

15 – XV

20 – XX

Since 33 is XXXIII, it would stomp its hoof 6 times.

They give the number of stomps for numbers 1 to 10:

1 2 3 2 1 2 3 4 2 1

If the sequence repeats starting at 10, then we have:

1 2 3 2 1 2 3 4 2 (for 1-9)

1 2 3 2 1 2 3 4 2 (for 10-18, note 2 stomps at 15)

1 2 3 2 1 2 3 4 2 (for 19-27, note 2 stomps at 20)

1 2 3 2 1 2 3 4 2 (for 28-36)

So, if the above pattern holds, there should be 2 stomps for 33 as well. Not very mathematical, I suppose…

it seems like multiples of 4 are divided by 2 and thats the number of stomps, prime numbers are 3 stomps, multiples of 5 are 1 stomp and multiples of 3 are 2 stomps

but 20 is a multiple of 5 and 4 so i dont think thats right, sorry i cant help u

1, 2, 3, 2, 1, 2, 3, 4, 2, 1, 2 ,3, 4, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 6, 1, 2, 3, 4, 5, 6, 1, 2, 3.<----#33