In lotto 54 a bettor selects six numbers for 1 to 54 (without repetitiion)……?
What is the probability of:
1.all six winning numbers
2.exactly 5 of the winning numbers
3.exactly three of the winning numbers
4.no winning numbers..
A little confused about this one it is supposed to use Hypergeometric distribution and i dont understand
Favorite Answer
combinations
so 1/18595558800
that is the first one
Edit- sorry i made a mistake it should
actually be 25827165 possibilities
because i forgot to divide it by 720 because
that is 6 factorial.
the second one is
89677.65625 or 25827165 / 288
the third one is
74.662248496762257169287696577243
or 25827165 / 345920
and the last one is
2.1046440731997817383872500796968
or 25827165 / 12271512
the formula is
C(n, k)
P = ————————–
C(k, m) * C(n-k, k-m)
P is possibilities
C is the combinations button on your calculator
it might look like nCr
the n(54) is how many numbers altogether
the k(6) numbers picked out
the m(0-6) is the number of winning numbers
all of the answers are how many possibilities
just do 1/ number of bossibilities
to find the probability
1 day ago – Edit – Delete
Source(s):
http://www.saliu.com/oddslotto.html
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