A few days ago
I am only P5, I want to know how to answer this question..?
Town A and B are 435km apart. At 0915, a car left Town A and travelled towards Town B at a constant speed of 80km/h. At the same time, a lorry left Town B and travelled towards Town A at a constand speed. When they met, the car had travelled a distance of 240km.
What time did they meet?
What was the lorry’s speed?
Top 2 Answers
A few days ago
Favorite Answer
Let the first car left Town A towards Town B is Va, and the speed is 80km/hr (Va = 80km/hr)
Let the distance between Town A and Town B is L, and L = 435km.
Let the speed of Lorry is Vb, and the travelled distance is d = 240km
The travelled distance of first car
= L – d
= 435 – 240
= 195km
Time for the car and lorry meeting together is the first car achieve 195km (travelled distance of the first car)
Va = 195km / time
time = 195km / Va
time = 195km / 80km/hr
time = 2.4375hrs
time = 146.25mins (2hrs and 26.25mins)
First question: What time did they meet?
Meeting time = 09:15 + time
= 11:41:25
Second question: What was the lorry’s speed?
Lorry’s speed is its travelled distance over their travelling time
Lorry’s speed = d / time
= 240 / 2.4375
= 98.46 km/hr
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A few days ago
Better for you to make a picture. Draw a line, and put the cars on the line. Make the scale, and you put the dot on the line where the cars met.
It works for me.
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