A few days ago
Finding Derivative ln?
ln(sec(8x)+tan(8x))
Top 2 Answers
A few days ago
Favorite Answer
You’re going to need the Chain Rule. Remember,
d/dx ln(x) = 1/x
So,
d/dx ln(sec(8x) + tan(8x)) =
1/(sec(8x) + tan(8x)) * d/dx(sec(8x) + tan(8x))
You should be able to get it from there. You’ll need the Chain Rule again, twice.
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A few days ago
first of all, ln(sec(8x)+tan(8x)) is same as ln(sec(8x))*ln(tan(8x)), then you do product rule. (info you need = der of ln(x) is 1/x, der of sec(x) is sec(x)tan(x), and der of tan is sec(x)^2)
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