0+3y=-4, then divide by 3, and then

y = -4/3, and the point is (0,-4/3), not an easy one to graph.

An easier point is to put 0 in for y. then,

x + 3(0) = -4 or simply, x=-4, and the point is (-4,0), easy to graph.

Check the other points also — they don’t work!

-9 + 3(1) = -6, not -4

and -3 + 3(-1) = -6, not -4.

Hmmm, I’m beginning to think you wrote the equation in here wrong and that -4 was meant to be a -6, then all 3 pts. would work!

For Q2, the two points you have do check all right, but you need a 3rd point to get a line (NOT a triangle). Try using a 0 for y and you’ll get 2x-0=-2, or x=-1, so your 3rd point is (-1,0). That will do it!

Q1.

x + 3y = 4 can be written:

3y = 4 – x

y = -(1/3)x + 4/3

That graph has a gradient -1/3, and therefore seems to form a triangle with the axes. Only the sloping line is the graph of the function. The axes are not.

Q2.

2x – y = 2

y = 2x – 2

This graph has a gradient 2.

As x goes 0 1 2 3 4

y goes -2 0 2 4 6

Again, the graph is just the single sloping line, even though it seems to form a triangle with the axes near the origin.

Any straight line graph which does not pass through the origin (0,0) will seem to form a triangle in some position.

Some of this might be redundant, but I just thought I’d work it out from the beginning.

Number 2:

2x-y= -2

-y= -2x-2 (subtract 2x from both sides)

y= 2x+2 (divide both sides by -1)

So now you know 2 things. Since m= slope, in this case slope is 2. Slope is rise over run, so the line will go up two and over one. Also, the intersect is at (0,2).

So by adding 2 to the y values and 1 to the x values you can come up with more coordinates. Here are some:

x y

0 2

1 4

2 6

-1 0

Since it’s a linear equation, you shouldn’t have any more problems with triangles.