first, lets remember in multiplication and division, (+) x (+) = (+), (-) x (-) = (+), (+) x (-) = (-). In adding and subtracting, carry the sign of the bigger number. Standard operations, (MDAS), do multiplication, division, addition and subtraction in order. lets try this case: (3x^2 + x + 1)(2x – 3)

lets do the multiplication first. multiply both sides.

(3x^2)(2x) = 6x^3 (both positive, add the exponents; 2+1=3.

(3x^2)(-3) = -9x^2 (multiplying (-) and (+) = (-)

(x)(2x) = 2x^2 (add the exponents when multiplying.

(x)(-3) = -3x

(1)(2x) = 2x

(1)(-3) = -3x

the results would be

6x^3 -9x^2 +2x^2 -3x +2x -3

in simplifying, combine those with same exponents.

6x^3

(-9x^2 +2x^2) = -7x^2

(-3x +2x) = -1x or simply -x

-3

so that would be 6x^3 -7x^2 -x -3.

p.s. im not really sure about this. heheh pls let me know if my answer is right or wrong. thanks! I think its been a decade since I last did this.

take the small bracket and multiply each term by the big bracket

=(6x^3+2x^2+2x)-9x^2-3x-3

=6x^3-7x^2-x-3

For the second one use the same idea:

=4x^2-3xy+20xy-15y^2

=4x^2+17xy-15y^2

4x^2 – 15y^2

but.. maybe on your public library site there mite be a online hw tutor because i live in sf and our libary site has one

6x^3-7x^2-3x-3

4x^2-3xy+20xy-15y^2

4x^2+17xy-15y^2