A few days ago
Anonymous

This question is about the properties and reactions of several substances.?

Zinc salt “N” dissolves in water to form a colourless solution —> add aqueous ammonia —> forms a white precipitate “O” that dissolves in excess reagent.

Zinc salt “N” dissolves in water to form a colourless solution —> add dilute nitric acid and aqueous silver nitrate to form a white precipitate “P”.

Q1: Name the compound of the white precipitate “P”, name the compound of the white precipitate “O”, name the compound of the salt “N”.

Q2: Write the chemical equation for all the three reactions.

Q3: Name two substances you could react together to make zinc salt “N”.

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Top 3 Answers
A few days ago
smilam

Favorite Answer

This is just a guess, but I know that AgCl is a white precipitate, so maybe the zinc salt is ZnCl, I’m not sure because ZnCl2 is blue or green, but maybe ZnCl could be colorless.

The zinc + ammonia reaction could either be Zinc hydroxide which would be a precipitate or it could form a complex like Zn(NH3)2 + and then when you add more ammonia it turns into Zn(NH3)4 + and dissolves.

If the salt is ZnCl, you would just react Zn metal with Chlorine gas.

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4 years ago
Anonymous
Ionic bonding is on an analogous time as 2 or extra efficient atoms adhere to a minimal of one yet yet another using their cost. The classic social accumulating is that of NaCl, or table salt. Sodium (Na) has an atomic sort of eleven. There are 2 electrons in its first skill element, 8 contained interior the 2nd and one million extra efficient contained interior the 0.33. (count extensive style extensive style ’em up: 2+8+one million=eleven). Sodium hates this and is extra efficient than prepared to push that outer electron on yet yet another atom. Doing so, however, converts the Na atom to a cation (negatively charged.) Chlorine has an atomic sort of 18. There are 2 electrons in its first skill element, 8 contained interior the 2nd and 7 contained interior the 0.33. Cl, too, hates this. It desires to have 8 electrons in its thrid element; consequently, it is going to “rob” electrons because of fact it comes into touch with them. Doing so, however, will make it an anion (negatively charged). See what’s coming? Sodium (Na) and Chlorine (Cl) on an analogous time as entering into touch will bond IONICLY. Sodium pushes its electron off directly to Chlorine, it relatively is happy to have it. Sodium will become charged +one million, Chlorine will become costs -one million. using their costs, they “stick”, in an attempt to talk. certainly one in all those bonding is optimal situation-unfastened in inorganics and metals.
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A few days ago
Bonathon M
Yea I’ll answer this question: Uhhhhh what?
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