1st method

1. X + Y= -11

2. 2X – Y = 32

3. Now look at the positve and the negative y in these equations. If it is like this you can add these equations together, allowing you to get X alone.

4. 3X = 21, divide each side by 3.

5. X = 7

6. substitute x for 7 in the first equation.

7. 7 + Y = -11

8. subtract 7 from both sides. Y= -18

Second Method

1. X + Y= -11

2. 2X – Y = 32

3. Now, in the first equation, move the X to the other side.

4. Y = -11 – X

5. substitute this into the second equation

6. 2X – (-11 – X) = 32, use distributive property to multiply negative 1 into both -11, and -X

7. 2X +11+X = 32 is the same as 3X +11= 32

8. subtract 11 from both sides

9. 3X = 21

10. X = 7

11. substitute the 7 into the first equation again

12. 7 + Y = -11

12. subtract 7 from both sides

13. Y= -18

Now substitute these values into the second equation. The numbers, 7 and -18 make these equations true. Thanks, hope you liked my answer.

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2x – y = 32 2x – y = 32 plug in for y and x = 7

Solve using substitution or elimination…. there are other ways but this is what is taught first usually. I used elimination !

Final Answer: X = 7 and Y = -18 … Hope that helped : )

y + x = -11

2y – x = 32

So if you add both problems together you get:

(y + 2y) + (x + -x) = (-11 + 32)

3y = 21

y = 7

now that you know y = 7, just substitute it in the original problem.

(7) + x = -11

x = -18.

Your answer is x = -18, y = 7

let the 2 numbers be x, y

x+y = -11

2x-y = 32

Come on, struggle a bit and do it yourself instead of throwing up your hands…