How do I find the area of this right triangle?

The only thing I’m given is that the hypotenuse is 9. Thank you!

Top 4 Answers

A few days ago

wry humor

Favorite Answer

You have to assume that the right triangle is also equilateral since you aren’t given other parameters. In a right triangle, the length of the hypotenuse squared = the sum of the squares of the 2 sides. Therefore c^2 = a^2 + b^2. Since a = b, then c^2 = 2a^2 = 9. The area of a triangle = 1/2 (b) x (h). The base(b) is the horizontal side and the height(h) is the vertical side.

You do the math.

A few days ago

Anonymous

A squared + B squared equals c squared. The hypotenuse = C = 9. Since it’s a right triangle A=B. So…2 (a^2)=9*9;

a^2=40.5; a=6.36396.

Area=1/2 * A * B = 1/2 * 6.36396 * 6.36396 = 20.24994=20.25

A few days ago

meiwei.2310

This is a bit complicated..u noe phythagores thereom..

one of d sets r 3.4 and 5…

d hyphotenuse of d right angled triangle is 9cm which is 5 in d set

if we want to know d side…

9/5 times 3 = 5.4

9/5 times 4 = 7.2

so (7.2 times 5.4 ) divided by 2

= 19.44 cm

A few days ago

Anonymous

you can’t . need more information

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How do I find the area of this right triangle?

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