A few days ago
Square roots .. Confused !?
ok i don’t get this one either.. what does this question mean? Find a number with a square root between each of the following numbers.
6 and 7 _____
5 and 6 _____
10 and 11 _____
12 and 13 _____
13 and 14 _____
15 and 16 _____
( the ___’s are where you put the answer )
Top 5 Answers
A few days ago
Favorite Answer
Actually, 6 is the square root of 36. 36 is the square of six. I don’t know what the question is asking, unless you choose a number between six an seven (i.e. 6.5) and square it. Same for the rest.
EDIT– the answer that said that 36 is the square root of 6 is gone now 🙂
0
A few days ago
since the square root of 36 is 6 and the square root of 49 is 7 you can pick any number between 36 and 49
likewise sqrt[25] = 5 and sqrt[6] = 36 so you can pick a number between 25 and 36
ex: possible answers
37
26
101
145
170
226
0
A few days ago
Ok, square each number then choose a number in between the two products.
6 and 7 = 36 and 42 so choose any number between those
5 and 6 = 25 and 36 so choose any number between those
0
4 years ago
howdy, It helps to think of of sq. root of 6 as sq. root 3 x sq. root 2. this type you in hassle-free words multiply the as you may desire to eg: (x+y)(a+b) (ax)+(ya)+(bx)+(yb) as quickly as we multiply out your equation (Im writing as pairs so as which you will hit upon extra effective for sure): (utilising the shrink back because of the fact the sq. root photograph) (5/3)(/6) + (-2/3)(5/3) +(-3/6)(-2/3) + (/6)(-3/6). on an identical time as multiplying squareroots of an comparable fee (eg. /3 x /3 = 3) The sq. roots cancel. So we then understand that /6 is an comparable as /3 x /2 Sub that throughout the time of place for equations the area /6 is situations by using utilising /3 (5/3)(/2x/3) = 5/3 x /2/3 = 15/2 (-2/3)(5/3) = 3 x (5x-2) = -30 (-3/6)(-2/3) = 18/2 (/6)(-3/6) = -18 Now you in hassle-free words sub back indoors the basically perfect values. 15/2 – 30 + 18/2 – 18 and simplify.
0
A few days ago
you are really confused. I think you should ask your teacher.
0
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