first, rewrite the problem grouping it as follows:

(x^2 + 12x + 36) – 9y^2

Now, factor the trinomial since it is a perfect square:

(x + 6)^2 – 9y^2

This is the difference of two squares. Remember the special factors for the difference of two squares, a^2-b^2 = (a-b)(a+b), and apply it here, carefully, using x+6 for a and 3y for b:

(x + 6 – 3y)(x + 6 + 3y)

that’s it for #1.

#2) You’ll have to factor by grouping here also, to start with:

(x^3 – xy^2) + (x^2y – y^3)

Now factor each group separately,

x(x^2-y^2) +y(x^2 – y^2)

Notice that what is in the parenteses is exactly the same expression AND it is also the difference of two squares, so continue by first factoring out the same expressions from each term:

(x^2 – y^2)(x + y), almost done, the last step simply factors the difference of two squares:

(x – y)(x + y)(x + y) done!

#3) Hmmm. . . not sure about this one, sorry.

#2: You are going to have something that looks like this when you factor it (x^2 – y^2 )( _ + _ ).

#3: It doesnt seem to be complete, but it looks like it just repeats. If this is the case then you just take the number of terms, n, and multiply it by the expression. So you would get n(x-3)^2(2x+1)

Awh I dont know what Im talking about