A few days ago
stud1

Some math homework– need help please?

Hello…

I have a math question I am unsure of,

As a soft ball is being caught by a player, its speed goes from 32.5 m/s to 0 m/s in about 0.0050 sec. The mass of the ball equals 0.150 kg.

What is the acceleration of the ball, & what is the force in newtons (n=m*a)

thanks for your help– bless u

>>10 points?

Top 3 Answers
A few days ago
Gerardo G

Favorite Answer

a= (Vo-V1)/t = – 6500 m/s2

F= m *a = 975 N

0

A few days ago
.
a= (Vo-V1)/t = – 6500 m/s2

F= m *a = 975 N

0

A few days ago
Anonymous
…………………… Terminal Speed – Initial Speed

Acceleration = ——————- ——————

………………. …………………… Time

………………….. 0 m/s – 32.5 m/s

So… … ………. ——————–

………………………. 0.005 s

————————————————-

Acceleration = – 6500 m/s^2 (metres per square second)

————————————————-

Force (N) = Mass x Acceleration…

So….. 0.15 kg x -6500 m/s^2

Force = – 975 kg-m/s^2 (kilogram-metres per square second)

…. ….. …. .. .. 975 kg-m/s^2

Force can’t be negative…

(kg-m/s^2 = Newton)

——————————

Force = 975N

——————————

Hope this helps!

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