A few days ago
solve: e^(ax) = Ce^(bx)?
solve: e^(ax) = Ce^(bx)?
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A few days ago
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you want to solve for x, start by dividing both sides by e^(bx) (which is the same as multiplying by e^(-bx)): e^[(a-b)x]= C. Now take the natural logarithm of both sides
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