A few days ago
Simple Calculus problems help. PLEASE?
1)
lim f(x)=7
x–>3
Is it possible for this statement to be true and yet f(3)=9? EXPLAIN (This is what I need!! EXPLAIN IT!)
If the statement above is true, is the function continuous at x=3? EXPLAIN
2)
Evaluate:
lim x+3/x-3
x–>3
The answer is Does not Exist but why???
Top 2 Answers
A few days ago
Favorite Answer
1. Yes, it’s possible. You can define a function as f(x)=x+4 when
(-inf,3);(3,inf) and f(x)=9 when x=3. For this case, the limit would indeed be 7.
2. The limit fails to exist because as x approaches 3 from the left, the function goes to negative infinity. As x approaches 3 from the right, the function goes to postive infinity. Thus, there is no common value that the function approaches as x goes to 3.
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4 years ago
hi Mitch. I regarded into the two solutions and curiously in case you get d2/dx they the two paintings out to be the comparable. subsequently, i does not difficulty approximately it. i did not take a glance at your calculations. hopefully you began out with the quotient rule. yet another element why that’s not important is when you consider which you’re besides squaring your denominator which cancels out the full theory of having a thoroughly diverse answer. desire this helped.
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