project SPM 2007 for additional mathemtics?
In the second year, Ang receives a 10% increment in his monthly pay. On the other hand, the commission received by Bakar is reduced by RM50 for each subsequent month. In addition, the profit made by Chandran is reduced by 10% for each subsequent month.
1)What is the percentage change in their total income for the 2nd year compared to the 1st year? Comment on the answers.
2)tota lthey will receive in 1st year?
Favorite Answer
Ang: Year 1: Gets 2000 per month.
Year 2: Gets 2000*(1.1) = 2200 per month
Annually: Year 1 = 2000*12 = 24000
Year 2 = 2200*12 = 26400
Bakar: Year 1: 1000 for month 1, 1000 + 100 for month 2, 1000+100+100 for month 3, etc.
Year 2: He will be making 1000 + 100(12) = 2200 at the beginning of year 2. So in year 2 he will make 2200 + 2200 – 50 + 2200 – 50-50, etc.
Annually: Year 1 (1000)+(1000 + 100) + (1000+100+100) + … + 1000 + 11*100
= 1000*12 + 100+200+…+1100
=12000 + 100 * (11*12)/2
=12000 + 50*132
=12000 + 6600
=18600
Year 2 – 2200 + 2200 – 50 + 2200 – 100 + … + 2200 – 50*11
= 2200*12 – (50+100+150+…+550)
=26400 – 50*(1+2+…+11)
=26400 – 50*(11*12)/2
=26400 – 25*132
=26400 – 3300
=23100
Chandran: Year 1: 100 in month 1, 100*1.5 in month 2 100*1.5*1.5 in month 3, etc.
Year 2: At the beginning of year 2, he will make 100*1.5^12 = X. So in year two he will make X + X(1-.1)+X(1-.1)(1-.1), etc.
Annually:
Year 1: 100 + 100*1.5 + 100*1.5^2+…+100*1.5^11
=100(1+1.5+1.5^2+1.5^11)
=100*(1-1.5^12)/(1-1.5)
=25,749
Year 2: X + .9X + .9^2X + … + .9^11X
=x*(1+.9 + … + .9^11)
=X*(1-.9^12)/(1-.9)
=93,102
Summary: Year 1: 24000+18600+25479 = 68079 (answer to #2)
Year 2:26400+23100+93102 = 142602
#1: 142602/68079 – 1 = 109% – even though their income started to decrease in year 2, their starting income in year 2 was significantly higher than in year 1 and did not decrease as quickly as it had increased in year 1.
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